(x^2-2x+5)=2

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Solution for (x^2-2x+5)=2 equation:


Simplifying
(x2 + -2x + 5) = 2

Reorder the terms:
(5 + -2x + x2) = 2

Remove parenthesis around (5 + -2x + x2)
5 + -2x + x2 = 2

Solving
5 + -2x + x2 = 2

Solving for variable 'x'.

Reorder the terms:
5 + -2 + -2x + x2 = 2 + -2

Combine like terms: 5 + -2 = 3
3 + -2x + x2 = 2 + -2

Combine like terms: 2 + -2 = 0
3 + -2x + x2 = 0

Begin completing the square.

Move the constant term to the right:

Add '-3' to each side of the equation.
3 + -2x + -3 + x2 = 0 + -3

Reorder the terms:
3 + -3 + -2x + x2 = 0 + -3

Combine like terms: 3 + -3 = 0
0 + -2x + x2 = 0 + -3
-2x + x2 = 0 + -3

Combine like terms: 0 + -3 = -3
-2x + x2 = -3

The x term is -2x.  Take half its coefficient (-1).
Square it (1) and add it to both sides.

Add '1' to each side of the equation.
-2x + 1 + x2 = -3 + 1

Reorder the terms:
1 + -2x + x2 = -3 + 1

Combine like terms: -3 + 1 = -2
1 + -2x + x2 = -2

Factor a perfect square on the left side:
(x + -1)(x + -1) = -2

Can't calculate square root of the right side.

The solution to this equation could not be determined.

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